dateToNumber

Description

Convert a date to a float number, based on Jan 1st 00:00:00 = 0 and Dec 31st 23:59:59 = 1. The same day and time in leap year will be different after 28th of February and 23:59 on 31st of December will be 1.00274.

This is how this command works. The 365 days of the year are presented in range 0..1. So each day will be:

1 / 365 = 0.00273973

In a leap year there are 366 days, so the range will increase by 1 day:

1 / 365 * 366 = 1.00274

In short, in a normal year the command returns in range 0...1 in a leap year it will return in range 0...1.00274.

Syntax

dateToNumber date

Parameters:

date: Date

Returns: Number

Examples

Example 1

_float = dateToNumber [2035, 7, 6, 12, 0]; // 0.510959

Example 2

dateToNumber date; // returns float number for the current date

Example 3

Calculate days from 1/1/1970:

_fnc_daysFromEpoch =
{
    private _year = param [0];
    private _days = 0;
    for "_i" from 1970 to _year - 1 do
    {
        _days = _days + round linearConversion [0, 1, dateToNumber [_i, 12, 31, 23, 59], 0, 365, false];
    };

    _days + linearConversion [0, 1, dateToNumber _this, 0, 365, false];
};

hint str (date call _fnc_daysFromEpoch);